Sulphuric acid is an Oxoacid having two hydroxyl groups. BaO_{2} is a greyish-white powder and non-combustible material. Let us discuss what happens when they are reacted together.

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**BaO _{2} has a molecular weight of 169.33 g/mol. Its Hydrogen bond acceptor count is 2. It has a mật độ trùng lặp từ khóa of 5.68 g/cm3. H_{2}SO_{4} has a tall peak of 860 in the linear ion trap instrument. H_{2}SO_{4} has a**

**heavy atom count of 5.**

Let us discuss the product, type, and balancing of this reaction.

**What is the product of H**_{2}SO_{4} and BaO_{2}?

_{2}SO

_{4}and BaO

_{2}?

**H _{2}SO_{4} and BaO_{2} have the following products. Barium sulfate (BaSO4) and water (H_{2}O).**

**BaO _{2} + H_{2}SO_{4} → BaSO_{4 }+ H_{2}O_{2}**

**What type of reaction is H**_{2}SO_{4} + BaO_{2} ?

_{2}SO

_{4}+ BaO

_{2}?

**The reaction between H _{2}SO_{4} plus BaO_{2} is a Double displacement reaction.**

## **How vĩ đại balance H**_{2}SO_{4} + BaO_{2} ?

_{2}SO

_{4}+ BaO

_{2}?

**The number of molecules in the reactants and product are equal in this reaction of H _{2}SO_{4 }+ BaO_{2} hence need not be balanced.**

**BaO _{2} + H_{2}SO_{4} → BaSO_{4 }+ H_{2}O_{2}**

**H**_{2}SO_{4} + BaO_{2} titration ?

_{2}SO

_{4}+ BaO

_{2}titration ?

**In the reaction between H _{2}SO_{4} and BaO_{2}, Titration doesn’t really occur because H2SO4 is a strong acid and thus cannot be used for titration.**

**H**_{2}SO_{4} + BaO_{2} net ionic equation ?

_{2}SO

_{4}+ BaO

_{2}net ionic equation ?

**H _{2}SO_{4} and BaO_{2} have the following Ionic equation, We should go through the steps vĩ đại get vĩ đại the net ionic equation**.

**Create a balanced chemical equation and represent the physical states of the reactants and the products.****BaO**_{2 }(aq) + H_{2}SO_{4 }(aq) → BaSO_{4 }(aq)_{ }+ H_{2}O_{2}(aq)**Salts, acids, and bases dissociate into ions, but pure substances and molecules fail vĩ đại vì thế so sánh. The final equation after dissociation is****Ba**^{2+}+ O_{2}^{2-}+ 2 H^{+}+ SO_{4}^{2-}→ Ba^{2+}+ SO_{4}^{2-}+ 2 H^{+}+ 2 O^{2-}

**H**_{2}SO_{4} + BaO_{2} conjugate pairs ?

_{2}SO

_{4}+ BaO

_{2}conjugate pairs ?

**H _{2}SO_{4} and BaO_{2} have the following conjugate pairs **

^{–}HSO_{4}is the conjugate base of H_{2}SO_{4}.**BaO**_{2}has no acid-base conjugate pair.

**H**_{2}SO_{4} + BaO_{2} reaction enthalpy ?

_{2}SO

_{4}+ BaO

_{2}reaction enthalpy ?

**H _{2}SO_{4} and BaO_{2} reaction, their enthalpy has not been determined.**

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**Stoichiometry has yet vĩ đại be determined.**

**H**_{2}SO_{4} + BaO_{2} intermolecular forces ?

_{2}SO

_{4}+ BaO

_{2}intermolecular forces ?

**The reaction between H _{2}SO_{4} and BaO_{2} has the following intermolecular forces**.

**BaO**._{2}has an Ionic force**H**_{2}SO_{4}_{ }has nài der Waals**dispersion forces and dipole–dipole interactions and hydrogen bonding.**

**H**_{2}SO_{4} + BaO_{2} a buffer solution ?

_{2}SO

_{4}+ BaO

_{2}a buffer solution ?

**H _{2}SO_{4} and BaO_{2} as a buffer are not possible as H_{2}SO_{4 }is used. A buffer solution cannot be formed by a strong acid.**

**Is H**_{2}SO_{4} + BaO_{2} a complete reaction ?

_{2}SO

_{4}+ BaO

_{2}a complete reaction ?

**H _{2}SO_{4} + BaO_{2} is a complete reaction. . Barium sulfate(BaSO_{4}) and water (H_{2}O) as their products.**

**BaO _{2} + H_{2}SO_{4} → BaSO_{4 }+ H_{2}O_{2}**

**Is H**_{2}SO_{4} + BaO_{2} an exothermic or endothermic reaction ?

_{2}SO

_{4}+ BaO

_{2}an exothermic or endothermic reaction ?

**H _{2}SO_{4} + BaO_{2} is an exothermic reaction because heat is liberated.**

**Is H**_{2}SO_{4} + BaO_{2} a redox reaction ?

_{2}SO

_{4}+ BaO

_{2}a redox reaction ?

**H _{2}SO_{4} + BaO_{2} is not a redox reaction, as there is no change is observed in the oxidation number of Ba or Oxygen.**

**Is H**_{2}SO_{4} + BaO_{2} a precipitation reaction ?

_{2}SO

_{4}+ BaO

_{2}a precipitation reaction ?

**H _{2}SO_{4} + BaO_{2} is a precipitation reaction. BaSO4 is obtained as a residue.**

**Is H**_{2}SO_{4} + BaO_{2} a reversible or irreversible reaction ?

_{2}SO

_{4}+ BaO

_{2}a reversible or irreversible reaction ?

**H _{2}SO_{4} + BaO_{2} is the irreversible reaction because heat is liberated, and the residue is obtained.**

**Is H**_{2}SO_{4} + BaO_{2} displacement reaction ?

_{2}SO

_{4}+ BaO

_{2}displacement reaction ?

**H _{2}SO_{4} + BaO_{2} is a double displacement reaction as Ba displaces H.**

#### Conclusion-

In this article, we have discussed the reaction between H_{2}SO_{4} and BaO_{2}, its balancing type, and other properties. BaO_{2 }is used in bleaching agents.

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